{
 "cells": [
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "$ \\displaystyle 17 - \\frac{81 \\cdot 97}{11 + 34 + x} + 93 = \\frac{1121}{34} $ `Ans` $ x = 57 $\n",
    "\n",
    "$ \\displaystyle \\frac{40 \\left(17 - 4 \\cdot 4\\right)}{4} = 10 $\n",
    "\n",
    "$ \\displaystyle \\frac{2523 \\left(63 + 83\\right)}{146 \\cdot 87} = 29 $\n",
    "\n",
    "$ \\displaystyle - 48 \\cdot 53 + \\frac{2193 \\cdot 48}{40} + 53 \\cdot 8 - \\frac{2193 \\cdot 8}{40} = 73 $\n",
    "\n",
    "$ \\displaystyle 48 - 84 - \\frac{x}{91} = \\frac{-3342}{91} $ `Ans` $ x = 66 $\n",
    "\n",
    "$ \\displaystyle \\frac{21 \\left(21 \\cdot 14 + 21 \\cdot 75 - 1829\\right)}{21} = 40 $\n",
    "\n",
    "$ \\displaystyle 13 + 47 x + 5 = 1428 $ `Ans` $ x = 30 $\n",
    "\n",
    "$ \\displaystyle \\frac{4559 \\cdot 76}{38 \\left(- 25 + 31 + 6 + 85\\right)} = 94 $\n",
    "\n",
    "$ \\displaystyle - \\frac{5720 \\cdot 29 + 5720 \\cdot 94}{123 \\cdot 27 - 123 \\cdot 92} = 88 $\n",
    "\n",
    "$ \\displaystyle \\frac{47 \\cdot 2 \\cdot 35 \\cdot 53 \\cdot 54}{47 \\cdot 12 + 3704 \\cdot 94} = 27 $\n",
    "\n",
    "$ \\displaystyle \\frac{51 + 55 + 69}{x} = 25 $ `Ans` $ x = 7 $\n",
    "\n",
    "$ \\displaystyle \\frac{- 17 + \\frac{2729 \\cdot 46}{23} + 97}{78} = 71 $\n",
    "\n",
    "$ \\displaystyle \\frac{- 40 + 8}{88} = \\frac{-4}{11} $\n",
    "\n",
    "$ \\displaystyle \\frac{54 \\left(9 \\cdot 56 - 500\\right)}{9} = 24 $\n",
    "\n",
    "$ \\displaystyle \\frac{65 \\left(38 - x \\left(22 - 77\\right)\\right)}{96} = \\frac{41795}{96} $ `Ans` $ x = 11 $\n",
    "\n",
    "$ \\displaystyle \\frac{66}{- \\frac{28 \\cdot 91}{x} + 38} = \\frac{473}{60} $ `Ans` $ x = 86 $\n",
    "\n",
    "$ \\displaystyle - 65 + \\frac{68}{x} = \\frac{-161}{3} $ `Ans` $ x = 6 $\n",
    "\n",
    "$ \\displaystyle \\frac{6435 \\left(12 + 77\\right)}{89 \\left(66 + 99\\right)} = 39 $\n",
    "\n",
    "$ \\displaystyle \\frac{9770 \\cdot 29}{29 \\left(29 \\cdot 65 + 69\\right)} = 5 $\n",
    "\n",
    "$ \\displaystyle \\frac{39 \\cdot 92 \\cdot 95}{75} = \\frac{22724}{5} $\n",
    "\n",
    "$ \\displaystyle \\frac{68 \\cdot 70}{92} = \\frac{1190}{23} $\n",
    "\n",
    "$ \\displaystyle \\frac{64 \\left(313 - 32 \\cdot 9\\right)}{32} = 50 $\n",
    "\n",
    "$ \\displaystyle \\frac{92 x}{25 - 38} = \\frac{-1748}{13} $ `Ans` $ x = 19 $\n",
    "\n",
    "$ \\displaystyle \\frac{70 + 1678}{92} = 19 $\n",
    "\n",
    "$ \\displaystyle \\frac{4 \\cdot 38}{197 \\cdot 2 - 4 \\cdot 89} = 4 $\n",
    "\n",
    "$ \\displaystyle x \\left(49 \\cdot 74 + 52\\right) = 55170 $ `Ans` $ x = 15 $\n",
    "\n",
    "$ \\displaystyle - 36 + 57 + \\frac{x}{80} = \\frac{217}{10} $ `Ans` $ x = 56 $\n",
    "\n",
    "$ \\displaystyle \\frac{17 \\cdot 52}{140} + \\frac{17 \\cdot 88}{140} = 17 $\n",
    "\n",
    "$ \\displaystyle 13 + 24 \\cdot 50 + 87 = 1300 $\n",
    "\n",
    "$ \\displaystyle \\frac{70 \\cdot 93 - 44310}{70 \\left(16 - 28\\right)} = 45 $\n",
    "\n",
    "$ \\displaystyle \\frac{162 \\cdot 2}{2 \\cdot 36 - 2 \\cdot 47 + 40} = 18 $\n",
    "\n",
    "$ \\displaystyle \\frac{8 - 88 + 630}{22} = 25 $\n",
    "\n",
    "$ \\displaystyle \\frac{65 + x}{20} = \\frac{9}{2} $ `Ans` $ x = 25 $\n",
    "\n",
    "$ \\displaystyle 56 + \\frac{x}{3} = \\frac{265}{3} $ `Ans` $ x = 97 $\n",
    "\n",
    "$ \\displaystyle \\frac{48}{6 + x} = \\frac{24}{47} $ `Ans` $ x = 88 $\n",
    "\n",
    "$ \\displaystyle \\frac{154 \\left(11 \\cdot 12 + 84\\right)}{9 \\cdot 12 \\cdot 7} = 44 $\n",
    "\n",
    "$ \\displaystyle \\frac{x}{62 - 68} = \\frac{-32}{3} $ `Ans` $ x = 64 $\n",
    "\n",
    "$ \\displaystyle \\frac{- 47 + 80 + 97}{12} = \\frac{65}{6} $\n",
    "\n",
    "$ \\displaystyle \\frac{32 \\left(42 + 96\\right)}{69 \\cdot 32} = 2 $\n",
    "\n",
    "$ \\displaystyle \\frac{x \\left(20 + 39\\right)}{22} = \\frac{295}{2} $ `Ans` $ x = 55 $\n",
    "\n",
    "$ \\displaystyle \\frac{- 16 \\cdot 6 + \\frac{21 \\cdot 51 \\left(- 359 \\cdot 16 - 359 \\cdot 89 + 37831\\right)}{359} - 6 \\cdot 89 + \\frac{37831 \\cdot 6}{359}}{51} = 8 $\n",
    "\n",
    "$ \\displaystyle \\left(33 - 58\\right) \\left(39 - \\frac{55 - 9}{x}\\right) = \\frac{-8200}{9} $ `Ans` $ x = 18 $\n",
    "\n",
    "$ \\displaystyle 50 + \\frac{x}{38} = \\frac{951}{19} $ `Ans` $ x = 2 $\n",
    "\n",
    "$ \\displaystyle x \\left(- 75 + 86\\right) = 99 $ `Ans` $ x = 9 $\n",
    "\n",
    "$ \\displaystyle \\frac{1109 - 34}{43} = 25 $\n",
    "\n",
    "$ \\displaystyle \\frac{62 x}{93} = 30 $ `Ans` $ x = 45 $\n",
    "\n",
    "$ \\displaystyle 18 + 9 x = 378 $ `Ans` $ x = 40 $\n",
    "\n",
    "$ \\displaystyle x \\left(29 - 62\\right) = -429 $ `Ans` $ x = 13 $\n",
    "\n",
    "$ \\displaystyle \\frac{15 \\cdot 56}{15 \\cdot 35 - 469} = 15 $\n",
    "\n",
    "$ \\displaystyle \\frac{341 \\cdot 45}{5 \\left(10 + 89\\right)} = 31 $\n",
    "\n",
    "$ \\displaystyle 59 + 88 x = 1819 $ `Ans` $ x = 20 $\n",
    "\n",
    "$ \\displaystyle \\frac{13 \\cdot 80}{260} = 4 $\n",
    "\n",
    "$ \\displaystyle 28 \\left(85 - x\\right) = 1904 $ `Ans` $ x = 17 $\n",
    "\n",
    "$ \\displaystyle \\frac{21 \\cdot 88}{x} = \\frac{462}{5} $ `Ans` $ x = 20 $\n",
    "\n",
    "$ \\displaystyle \\frac{11 \\cdot 59}{122} + \\frac{11 \\cdot 63}{122} = 11 $\n",
    "\n",
    "$ \\displaystyle \\frac{24 \\left(13 + 45\\right)}{29 \\cdot 6} = 8 $\n",
    "\n",
    "$ \\displaystyle \\frac{12 \\cdot 65 \\left(787 \\cdot 44 - 33440\\right) + 787 \\cdot 44 \\cdot 7 - 33440 \\cdot 7}{787 \\cdot 12} = 99 $\n",
    "\n",
    "$ \\displaystyle 37 \\left(- 98 + x\\right) = -1036 $ `Ans` $ x = 70 $\n",
    "\n",
    "$ \\displaystyle - 23 - 47 + 62 + 8 = 0 $\n",
    "\n",
    "$ \\displaystyle 12 - \\frac{80}{x} = 7 $ `Ans` $ x = 16 $\n",
    "\n",
    "$ \\displaystyle - \\frac{3 \\cdot 70}{3 \\cdot 2 - 76} = 3 $\n",
    "\n",
    "$ \\displaystyle \\frac{15 \\cdot 67}{55} = \\frac{201}{11} $\n",
    "\n",
    "$ \\displaystyle 87 \\left(57 - \\frac{x}{24}\\right) = \\frac{37381}{8} $ `Ans` $ x = 79 $\n",
    "\n",
    "$ \\displaystyle 4 \\left(x - 1\\right) = 96 $ `Ans` $ x = 25 $\n",
    "\n",
    "$ \\displaystyle \\frac{48 \\left(24 \\cdot 56 + 31\\right)}{125 \\cdot 24} = 22 $\n",
    "\n",
    "$ \\displaystyle \\frac{15 + 52}{69 x} = \\frac{67}{2484} $ `Ans` $ x = 36 $\n",
    "\n",
    "$ \\displaystyle \\frac{21 x}{97} = \\frac{147}{97} $ `Ans` $ x = 7 $\n",
    "\n",
    "$ \\displaystyle \\frac{28 \\left(7 \\cdot 24 - 157\\right)}{7} = 44 $\n",
    "\n",
    "$ \\displaystyle - 33 + \\frac{x}{31} = \\frac{-1021}{31} $ `Ans` $ x = 2 $\n",
    "\n",
    "$ \\displaystyle \\frac{200 \\cdot 81}{27 \\cdot 60} = 10 $\n",
    "\n",
    "$ \\displaystyle \\frac{436 \\cdot 75 \\cdot 96}{225 \\left(21 \\cdot 82 + 22\\right)} = 8 $\n",
    "\n",
    "$ \\displaystyle - \\frac{96 - 98}{48} + \\frac{x}{39} = \\frac{87}{104} $ `Ans` $ x = 31 $\n",
    "\n",
    "$ \\displaystyle \\frac{3 \\cdot 24}{10} + \\frac{3 \\cdot 46}{10} = 21 $\n",
    "\n",
    "$ \\displaystyle - \\frac{99}{2 - 35} = 3 $\n",
    "\n",
    "$ \\displaystyle - \\frac{512}{32 \\left(13 + 29 - 46\\right)} = 4 $\n",
    "\n",
    "$ \\displaystyle \\frac{- 99 + x}{15} = \\frac{-23}{5} $ `Ans` $ x = 30 $\n",
    "\n",
    "$ \\displaystyle - 34 + 49 x = 113 $ `Ans` $ x = 3 $\n",
    "\n",
    "$ \\displaystyle \\frac{2 \\cdot 21}{2 \\cdot 21 + 2 \\cdot 77 - 175} = 2 $\n",
    "\n",
    "$ \\displaystyle \\frac{15 \\cdot 65}{x} = \\frac{975}{41} $ `Ans` $ x = 41 $\n",
    "\n",
    "$ \\displaystyle \\frac{284}{35 + 36} = 4 $\n",
    "\n",
    "$ \\displaystyle \\frac{99}{61 - x} = \\frac{33}{14} $ `Ans` $ x = 19 $\n",
    "\n",
    "$ \\displaystyle \\frac{50 \\cdot 54}{36} = 75 $\n",
    "\n",
    "$ \\displaystyle \\frac{1056 \\cdot 52}{13 \\cdot 96} = 44 $\n",
    "\n",
    "$ \\displaystyle \\frac{83 \\left(17 - 77\\right)}{x} = \\frac{-415}{2} $ `Ans` $ x = 24 $\n",
    "\n",
    "$ \\displaystyle \\frac{24 \\cdot 63}{7 \\cdot 72} = 3 $\n",
    "\n"
   ]
  }
 ],
 "metadata": {
  "kernelspec": {
   "display_name": "Python 3",
   "language": "python",
   "name": "python3"
  },
  "language_info": {
   "codemirror_mode": {
    "name": "ipython",
    "version": 3
   },
   "file_extension": ".py",
   "mimetype": "text/x-python",
   "name": "python",
   "nbconvert_exporter": "python",
   "pygments_lexer": "ipython3",
   "version": "3.7.5"
  }
 },
 "nbformat": 4,
 "nbformat_minor": 4
}
